01

What Are Masonry Infill Walls?

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Definition and Context

Masonry infill walls (also called URM infills — Unreinforced Masonry) are non-load-bearing partition walls built inside the grid of RC (Reinforced Concrete) beams and columns. They typically consist of brick, hollow concrete block, or AAC panels, plastered on both sides.

In India, nearly every multi-storey RC frame building uses masonry infill walls extensively — for rooms, staircases, boundary walls, and external enclosures. The lower floors (like stilt/pilotis for parking) are often left open, while upper floors are fully infilled.

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The “Earthquake Laughed” Problem

Historically, designers treated infill walls as non-structural — they ignored them in structural models entirely. The RC bare frame was designed for seismic loads, while infills were assumed to just sit there harmlessly. In reality, infills interact significantly with the frame during earthquakes, completely changing the stiffness distribution, natural period, and failure pattern of the building. Many spectacular collapses — including Bhuj 2001, Nepal 2015 — were directly caused by soft-storey failure due to ignored infill effects.

Fig 1 — Three Common Building Configurations
Bare Frame No Infill No Infill No Infill No Infill Uniform Flexibility Fully Infilled Frame Masonry Infill Masonry Infill Masonry Infill Masonry Infill Uniform Stiffness ✓ Open Ground Storey OPEN (Parking) Masonry Masonry Masonry ⚡ Soft Storey Failure Fig 1: Three RC Frame Configurations
02

Why Infills Matter Seismically

🏗️ Bare Frame Model (Old Practice)

  • Higher natural period → lower seismic force
  • Infill mass included but infill stiffness ignored
  • Under-designed for actual seismic demands
  • Uniform storey stiffness assumed
  • Common in practice before 2016

✅ Infilled Frame (IS 1893:2016)

  • Shorter natural period → higher seismic force
  • Infill stiffness explicitly modelled as diagonal strut
  • More realistic distribution of storey forces
  • Detects irregularities introduced by infills
  • Required when SPD > 20%

🚨 Open Ground Storey (Worst Case)

  • Sudden stiffness discontinuity at ground level
  • Columns carry huge ductility demands
  • Weak storey + soft storey combined
  • 2.5× force multiplier required for OGS columns
  • Banned in Zones IV & V unless remediated
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Effect on Structural Parameters
ParameterBare FrameFully InfilledOpen Ground Storey
Natural Period THigh (longer)Short (lower)Between the two
Base Shear VBLower (unsafe)Higher (correct)Medium but concentrated
Ground Floor DriftModerateLow🔴 Very High
Stiffness IrregularityNoneNone (if uniform)🔴 Severe
Column Axial ForceModerateHigher (strut forces)🔴 Critical concentration
Short Column EffectPossible if partial infillIf restricted heightPossible at transitions
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Key Insight from IS 1893:2016 Preamble (Cl. 6.1.3)

Actual earthquake forces on structures are much higher than the design forces specified in the code. The code relies on inelastic behaviour (ductility) and overstrength to cover the deficit. When infills create a soft storey, this ductility demand concentrates brutally at the weak level — the building collapses before it can redistribute forces.

03

Structural Plan Density (SPD) — The Trigger Check

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What is SPD and Why Does it Trigger Infill Modelling?

Structural Plan Density (SPD) is the ratio of the cross-sectional area of all unreinforced masonry (URM) walls in a given plan direction to the total plan area of the floor, expressed as a percentage. It is defined in IS 1893:2016 Cl. 7.9 and cross-referenced in Table 6.

The concept is simple: if your building has a lot of masonry walls (high SPD), ignoring them in analysis will produce significantly wrong results. So IS 1893:2016 sets a threshold.

SPD = (Σ Aw) / Afloor × 100 %
Σ Aw Sum of cross-sectional areas of all URM infill walls in the considered direction at a given floor level (m²)
Afloor Total plan area of the floor (m²)
SPD Structural Plan Density (%)
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The 20% Rule — IS 1893:2016 Table 6 / Cl. 7.9

When SPD of URM infill walls exceeds 20% in any principal plan direction, the effect of URM infills shall be considered by explicitly modelling them in structural analysis as per Clause 7.9 (equivalent diagonal strut method). This is mandatory, not optional.

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How to Calculate SPD — Step by Step
  1. Identify all URM infill walls at a floor level in the direction under consideration (X or Y)
  2. Measure the thickness (t) and length (L) of each wall in that direction
  3. Compute Aw = t × L for each wall (cross-section perpendicular to that direction)
  4. Sum all Aw values: Σ Aw
  5. Divide by the total plan area of the floor: SPD = (Σ Aw / Afloor) × 100%
  6. Compare: if SPD > 20%, proceed with Clause 7.9 modelling
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Note on Direction

SPD is calculated separately for X and Y directions. A wall parallel to the X-direction resists forces in X. Check both directions independently — one may exceed 20% while the other does not.

04

Clause 7.9 — Modelling of URM Infill Walls

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Core Mandate of Clause 7.9

When SPD > 20%, the engineer must model URM infill panels as equivalent diagonal compression struts in the structural analysis. The infill is treated as a pin-jointed diagonal member that can only carry compression (no tension), connected between opposing beam-column joints.

The design forces for RC members (beams, columns, joints) shall be taken as the larger of:

  • Results from analysis of the building with infills modelled (infilled frame model)
  • Results from analysis of the building without infills (bare frame model)
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Why Both Models?

Infills can increase force demand in some members (due to strut action) and create different load paths. Running both bare-frame and infilled-frame analyses and taking the envelope ensures nothing is under-designed.

Key Rules for Modelling Infills per IS 1893:2016 Cl. 7.9
  • Infill panels are modelled as pin-jointed diagonal compression struts only — no moment transfer
  • The strut is placed diagonally in the panel, and it can only carry compressive force
  • Two struts (one for each loading direction) may be modelled per panel (X and Y)
  • The strut is NOT rigidly connected at the frame joints — it simulates the way infill leans against the frame
  • The modulus of elasticity of the masonry (Em) is taken as per IS 1905 provisions
  • The thickness of the strut equals the actual thickness of the infill wall (tinf)
  • Openings in infill walls significantly reduce effective strut width — special treatment needed
  • Partial-height infills (creating short-column effect) must be separately identified and checked
05

The Equivalent Diagonal Strut — Theory & Formula

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Physical Concept

When a masonry infill panel is subjected to lateral load, it interacts with the surrounding RC frame. Instead of the full wall engaging, the infill develops a diagonal compression zone — essentially acting like a diagonal brace. Holmes (1961), Smith (1962), and subsequent researchers showed this can be represented by an equivalent diagonal strut.

The width of this equivalent strut (w) determines the stiffness contribution of the infill to the frame. IS 1893:2016 adopts the FEMA 356 / ASCE 41 formulation.

Fig 2 — Equivalent Diagonal Strut Representation
Masonry Infill Panel Equivalent Strut (w × t) Pin Pin hcol Linf (panel length) w (strut width) θ EQ
w = 0.175 × (λ₁ × hcol)−0.4 × rinf
w Equivalent strut width (mm or m) — IS 1893:2016 Cl. 7.9 / FEMA 356
rinf Diagonal length of infill panel = √(hinf² + Linf²)
hcol Height of column between beam centrelines (mm)
λ₁ Stiffness parameter (mm⁻¹): see formula below
λ₁ = ⁴√[ (Em × tinf × sin 2θ) / (4 × Ef × Icol × hinf) ]
Em Modulus of elasticity of masonry infill (MPa) — typically 550 fm per FEMA 356
tinf Thickness of infill panel (mm)
θ Angle of diagonal strut to horizontal = arctan(hinf / Linf)
Ef Modulus of elasticity of frame material (MPa) — for RC: 5000√fck
Icol Moment of inertia of column section (mm⁴)
hinf Height of infill panel (centre-to-centre of beams, mm)
What λ₁ physically represents

λ₁ is the relative stiffness of the infill to the frame. A higher λ₁ means the infill is much stiffer relative to the column, so the contact zone is narrower and the strut width is smaller. A lower λ₁ (flexible frame, stiff infill) gives a wider strut. The 0.175 factor and the −0.4 exponent come from curve-fitting to experimental and FE results.

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Infill Masonry Properties (Typical Values)
Masonry Typefm (MPa)Em = 550 fm (MPa)Unit Weight (kN/m³)
Burnt brick — M1 mortar3.5 – 5.01925 – 275019.2
Burnt brick — M2 mortar2.5 – 4.01375 – 220019.2
Hollow concrete block2.0 – 3.51100 – 192512 – 15
AAC block1.5 – 2.5825 – 13756 – 8
Stone masonry5.0 – 8.02750 – 440022 – 26

fm = compressive strength of masonry prism. Use IS 1905 for actual values. Em = 550·fm is the FEMA 356 empirical formula commonly adopted.

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Short Column Effect — Critical Hazard from Partial Infill

When infill walls are partially built (e.g., up to window sill level only), they restrict the deformation length of the column. The effective length is shortened to the gap above the infill. During an earthquake, shear demand is concentrated in this short column segment, often causing brittle shear failure. IS 1893:2016 requires these partial-height infill conditions to be explicitly identified and the affected columns designed for the increased shear demand.

06

Stiffness Irregularity Due to Infills — IS 1893 Table 6

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Types of Vertical Irregularity Related to Infills

IS 1893:2016 Table 6 defines vertical irregularity types. Masonry infills directly contribute to two of these:

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Type 1a — Stiffness Irregularity (Soft Storey)

A storey whose lateral stiffness is less than 70% of the stiffness of the storey above, OR less than 80% of the average stiffness of the three storeys above it.

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Type 1b — Extreme Stiffness Irregularity (Extreme Soft Storey)

A storey whose lateral stiffness is less than 60% of the storey above, OR less than 70% of the average stiffness of the three storeys above. This is the open-ground-storey condition for most buildings.

When infills are present only in upper floors and absent at ground level (typical stilt building), the ground storey stiffness drops dramatically, triggering both Type 1a and 1b irregularities simultaneously.

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Consequences of Irregularity Classification
ConditionSeismic Zone IIZone IIIZones IV & V
Regular buildings — analysis method ESM or RSMESM or RSMRSM mandatory for >12m irregular
Soft storey (Type 1a) ESM allowedESM allowed🔴 RSM mandatory; special detailing
Extreme soft storey (Type 1b) — OGS 2.5× multiplier2.5× multiplier🔴 2.5× or explicit infill model; Zones IV/V: extremely discouraged
Weak storey Special design required🔴 NOT PERMITTED in Zones III, IV, V

ESM = Equivalent Static Method; RSM = Response Spectrum Method.

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Stiffness Irregularity Check — How to Perform It
  1. Model the building with infills as diagonal struts (if SPD > 20%)
  2. Extract the lateral storey stiffness Ki for each floor from the analysis (= storey shear / storey drift)
  3. Check if Ki ≥ 0.70 × Ki+1 (storey above)
  4. Check if Ki ≥ 0.80 × average(Ki+1, Ki+2, Ki+3)
  5. If either condition fails → Soft Storey (Type 1a); if Ki < 60% → Extreme (Type 1b)
  6. Apply required analysis method and design provisions
07

Clause 7.10 — Open Ground Storey (OGS) Design

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The Most Common Failure Mode in India

Open Ground Storey (OGS) buildings — with parking at ground level — are everywhere in Indian cities. Bhuj 2001, Sikkim 2011, Nepal 2015 all showed catastrophic OGS collapses. Clause 7.10 is IS 1893’s direct response to this epidemic of unsafe stilt buildings.

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Design Options under Clause 7.10

IS 1893:2016 Clause 7.10 provides two approaches for OGS buildings:

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Option A — Explicit Infill Modelling (Preferred)

Model the entire structure including infill struts in all storeys. The analysis will automatically capture the stiffness discontinuity at the open storey. Design the OGS columns and beams for the resulting forces. This is the more accurate approach required for buildings in Zones IV and V.

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Option B — 2.5× Multiplication Factor (Simplified)

The columns and beams of the open ground storey shall be designed for 2.5 times the storey shears and moments calculated under seismic loads in the bare frame analysis. Additionally, the structural shear walls, braces, or additional columns shall be provided to stiffen the OGS. The 2.5 factor represents the concentration of ductility demand at the open storey.

VOGS,design = 2.5 × VOGS,analysis
VOGS,design Design shear force for open ground storey columns/beams
VOGS,analysis Storey shear from bare frame seismic analysis at ground storey level
2.5 Amplification factor mandated by IS 1893:2016 Cl. 7.10 for OGS buildings
Remedial Measures Recommended by IS 1893:2016
  • RC Shear Walls: Provide RC structural walls in the ground storey extending to the foundation — this directly stiffens the OGS
  • Diagonal Bracing: Steel or RC diagonal braces in the open storey can compensate stiffness loss
  • Infill the Ground Storey: Add masonry infill walls (at least partially) in the ground storey — the most cost-effective retrofit
  • Increase Column Size: Larger columns with more ductile detailing per IS 13920:2016 to handle the extra ductility demand
  • Base Isolation: For critical structures, though expensive
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Related Standards

Ductile detailing of OGS columns MUST comply with IS 13920:2016 (special moment-resisting frame requirements). Seismic evaluation and retrofitting of existing OGS buildings is covered in IS 15988:2013.

Fig 3 — Stiffness Distribution: Regular vs. Open Ground Storey
Regular Infilled Frame Floor 4 Floor 3 Floor 2 Ground K = 100 K = 95 K = 92 K = 97 ✓ Uniform — No Irregularity Open Ground Storey Floor 4 Floor 3 Floor 2 Ground! K = 100 K = 95 K = 92 K = 20 ⚡ K = 20% of floor above → Failure! (Requires 2.5× force factor) → Storey Lateral Stiffness (relative units)
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Equivalent Diagonal Strut Calculator
IS 1893:2016 Cl. 7.9 | FEMA 356 Formulation | Also checks SPD and OGS Stiffness Ratio
Clear height of masonry panel (beam-to-beam)
Clear length of masonry panel
Nominal wall thickness (e.g. 230mm brick)
Column height c/c of beams
Prism strength; Em = 550 × fm will be used
Column dimension in direction of shaking
Total plan area of one floor
Sum of (t × L) for all URM walls in one direction
Stiffness ratio of ground floor to floor above (for irregularity check)
08

Key Takeaways & Design Checklist

IS 1893:2016 — Masonry Infill Design Checklist
#CheckClauseAction if Failed
1Calculate SPD in X and Y directions7.9 / Table 6If SPD > 20%, model infills as struts
2Compute equivalent strut width w for each panel7.9.1Use FEMA 356 formula; consider openings
3Run both infilled and bare frame analysis7.9Design for envelope (larger forces)
4Check stiffness irregularity: Ki ≥ 0.70 Ki+1Table 6 Type 1aClassify as soft storey; use RSM
5Check extreme irregularity: Ki ≥ 0.60 Ki+1Table 6 Type 1bOGS provisions: 2.5× or explicit model
6Check for partial-height infills (short column)7.9Design column for full short-column shear
7OGS columns: apply 2.5× force multiplier OR model infills7.10Provide shear walls or bracing in OGS
8Detail OGS columns per IS 13920:2016 (SMRF)Cross-refDuctile detailing mandatory for Zones III–V
9Check weak storey (lateral strength, not stiffness)Table 6 Type 2NOT permitted in Zones III, IV, V
10Verify natural period T with infills vs bare frame7.6Use shorter T for base shear calculation
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Common Mistakes to Avoid
  • Treating infill walls as non-structural (pure dead load) in seismic analysis — specifically prohibited when SPD > 20%
  • Using bare frame natural period T for design spectrum when infills are present — this underestimates base shear
  • Not identifying partial-height infills that create short column effects
  • Designing OGS columns for regular frame forces without the 2.5× multiplier
  • Ignoring the stiffness of infills when checking vertical irregularity
  • Not running both infilled and bare frame models and taking the design envelope
  • Assuming symmetric infill plan when infills are actually asymmetric — introduces torsion
  • Forgetting that infill removal (renovation) changes the irregularity profile post-construction
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The Big Picture

IS 1893:2016’s treatment of masonry infills represents a major step toward realistic seismic assessment of Indian RC buildings. The key philosophy is: infills are structural whether you want them to be or not. When you model them, you find the real vulnerabilities — the soft storeys, the short columns, the torsion — before the earthquake does. When you don’t, the earthquake finds them for you.